One end of a copper rod of length 1.0 m and area of cross-section `10^(-3)` is immersed in boiling water and the other end in ice. If the coefficient of thermal conductivity of copper is `92 cal//m-s-.^(@)C` and the latent heat of ice is `8xx 10^(4) cal//kg`, then the amount of ice which will melt in one minute is
A. `9.2xx10^(-3)kg`
B. `8xx10^(-3)kg`
C. `6.9xx10^(-3)kg`
D. `5.4xx10^(-3)kg`

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1 Answers

`H=(DeltaQ)/(Deltat)=(KA(0_(H)-0_(L)))/l`
`DeltaQ=mL`
`:.(mL)/(Deltat)=(KA(0_(H)-0_(L)))/l`
`:.m=(KA(0_(H)-0_(L))Deltat)/(lL)`
`=(92xx10^(-3)xx100xx60)/(1xx80xx10^(-3))`
`=6.9xx10^(-3)kg`

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