18gm water is added in a 200 gm sample of Oleum labeled as `109%`. The new labelling of the final sample is :

18gm water is added in a 200 gm sample of Oleum labeled as `109%`. The new labelling of the final sample is :
A. `106%`
B. `103%`
C. `100%`
D. `0%`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

Salim Ahmed Kawsar

Correct Answer - C
Minimum labelling of Oleum `= 100%`
All free `SO_(3)` is exhausted using `18gm` of water and pure `218gm H_(2)SO_(4)` formed.

4 views Answered 2023-02-05 15:29

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