The magnitude of the vector `X^(2)hat(i) + (X - 1) hat(j)` is same as that of the magnitude of vectore `-hat(j) + (X^(2) - 1) hat(k)`. The value of x

Question

The magnitude of the vector `X^(2)hat(i) + (X - 1) hat(j)` is same as that of the magnitude of vectore `-hat(j) + (X^(2) - 1) hat(k)`. The value of x

The magnitude of the vector `X^(2)hat(i) + (X - 1) hat(j)` is same as that of the magnitude of vectore `-hat(j) + (X^(2) - 1) hat(k)`. The value of x is
A. 1
B. `-1`
C. 0
D. 2

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - B
`sqrt((x^(2))^(2) + (x - 1)^(2)) = sqrt((1)^(2) + (x^(2) + 1)^(2))`
`x^(4) + x^(2) + 1 - 2x = 1 + x^(4) + 1 + 2x^(2)`
`x^(2) + 2x + 1 = 0`
`(x + 1)^(2) = 0`
`x = -1`

5 views Answered 2023-02-05 15:29