The enthalpy change for the reaction `C_(3)H_(8)(g)+H_(2)(g) rarr C_(2)H_(6)(g)+CH_(4)(g)` at `25^(@)C` is -55.7 kJ/mol. Calculate the enthalpy of com
The enthalpy change for the reaction `C_(3)H_(8)(g)+H_(2)(g) rarr C_(2)H_(6)(g)+CH_(4)(g)` at `25^(@)C` is -55.7 kJ/mol. Calculate the enthalpy of combustion of `C_(2)H_(6)(g)`. The enthalpy of combustion of `H_(2)`, & `CH_(4)` are -285.8 & -890.0 kJ/mol respectively. enthalpy of combustion of propane is `-2220" kJ mol"^(-1)`.
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Correct Answer - `-1560.1" kJ mol"^(-1)`
`C_(2)H_(6)+7/2 O_(2) rarr 2CO_(2)+3H_(2)O`
`DeltaH=55.7+890-2220-285.8=-1560.1//kJ mol^(-1)`
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