Calculate the specific activity of a radioactive substance `._(98)^(250)Cf`, if its half life is `6.93 min`. Express your answer in terms of `10^(16)
Calculate the specific activity of a radioactive substance `._(98)^(250)Cf`, if its half life is `6.93 min`. Express your answer in terms of `10^(16) dps`. (Use : `N_(A)=6 xx10^(23)`)
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Correct Answer - [0090]
Sp. Activity `=lambda N=(1)/(250)xx6xx10^(23)xx(ln2)/(6.93 xx 60)=(1)/(250)xx6xx10^(23)xx(1)/(600)=400xx10^(16)dps`
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