Mass defect in the nuclear reactions may be expressed in terms of the atomic masses of the parent and daughter neucliders in place of their nuclear masses.
The mass defect of nuclear reaction : `._(4)Be^(10)rarr ._(5)B^(10)+ e^(-)` is
A. `Delta m="At. mass of " ._(4)Be^(10)-"At. mass of " _(5)B^(10)`
B. `Delta m="At. mass of " ._(4)Be^(10)-"At. mass of " _(5)B^(10)` -mass of one electron
C. `Delta m="At. mass of " ._(4)Be^(10)-"At. mass of " _(5)B^(10)` + mass of one electron
D. `Delta m="At. mass of " ._(4)Be^(10)-"At. mass of " _(5)B^(10)` - mass of two electrons

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Correct Answer - A
Nuclear reaction `._(4)B^(10) rarr . _(5)B ^(10)+ e^(-)`
Mass defect `=(4m_(p)+6m_(N))-[(5m_(p)+5m_(N))+m_(e)] `
`=(4m_(p)+6m_(N))-[(5m_(p)+5m_(N))+m_(e)] +4m_(e)-4m_(e)`
`=(4m_(p)+6m_(N)+4m_(e))-[5m_(p)+5m_(N)+5m_(e)]`
`="At mass of" ._(4)Be^(10)-"At. mass of " ._(5)B^(10)`

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