Acidified `K_(2)Cr_(2)O_(7)`, solution turns green when `Na_(2)SO_(3)` is added to it. Thus is due to the formation of
Acidified `K_(2)Cr_(2)O_(7)`, solution turns green when `Na_(2)SO_(3)` is added to it. Thus is due to the formation of
A. `Cr(SO)_(4))_(3)`
B. `CrO_(4)^(2-)`
C. `Cr_(2)(SO_(3))_(3)`
D. `CrSO_(4)`
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Correct Answer - A
`K_(2)Cr_(2)o_(7)+3Na_(2)SO_(4)to`
`3Na_(2)SO_(4)+K_(2)SO_(4)+Cr_(2)(SO_(4))_(3)+4H_(2)O`
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