If the equation x^2 – 4x + a = 0 has no real roots, then
If the equation x2 – 4x + a = 0 has no real roots, then
A) a ≤ 4
B) a < 2
C) a < 4
D) a > 4
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Correct option is (D) a > 4
Given that equation \(x^2-4x+a=0\) has no real roots.
\(\therefore(-4)^2-4\times1\times a<0\)
\(\Rightarrow16-4a<0\)
\(\Rightarrow16<4a\)
\(\Rightarrow\frac{16}4
\(\Rightarrow\) 4 < a
\(\Rightarrow\) \(a>4\)
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