1-Alkyl isocyanide on reduction with `Zn - Hg//HCl` gives
1-Alkyl isocyanide on reduction with `Zn - Hg//HCl` gives
A. `1^(@)` Amines
B. `3^(@)` Amine
C. N-Alkylalkanamine
D. N-Methylalkanamine
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Correct Answer - D
`RN overset(rarr)(=)C underset(4 [H])overset(Zn-Hg//HCl)(rarr) underset("N-Methyl alkanamine")(R-NH-CH_(3))`
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