How many Faraday are required to reduce 1 mole of `Cr_(2)O_(7)^(2-)` to `Cr^(3+)` in acid solutions ?
How many Faraday are required to reduce 1 mole of `Cr_(2)O_(7)^(2-)` to `Cr^(3+)` in acid solutions ?
A. 2
B. 3
C. 5
D. 6
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Correct Answer - D
(d) The reduction reaction in the acidic medium is :
`Cr_(2)O_(7)^(2-)+14H^(+)+6e^(-) to 2Cr^(3+)+7H_(2)O`
Thus, six Faraday of charge is required.
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