Standard reduction potentials for the half reactions are given below :
`F_(2)(g)+2e^(-) to 2F^(-)(aq) , E^(@)=+2.85" V "`
`Cl_(2)(g)+2e^(-) to 2Cl^(-)(aq) , E^(@)=+1.36" V "`
`Br_(2)(g)+2e^(-) to 2Br^(-)(aq) , E^(@)=+1.06" V "`
`I_(2)(g)+2e^(-) to 2I^(-)(aq) , E^(@)=+0.53" V "`
The strongest oxidising and reducing agents respectivity are :
A. `F_(2)` and `I^(-)`
B. `Br_(2)` and `Cl^(-)`
C. `Cl_(2)` and `Br^(-)`
D. `Cl_(2)` and `I_(2)`.

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Correct Answer - A
(a) More negative (or less positive) the value of reduction potential, stranger will be the reducing agent. Thus `l^(-)` is the strongest reducing agent. More positive is the values of reduction potential, stronger will be the oxidising agent. Thus, `F_(2)` is the strongest oxidising agent.

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