Two half cell reactions are given as : (i) `Fe_(aq)^(2+)+2e^(-) to Fe_((s)),E^(@)=-0.44" V "` (ii) `2H_((aq))^(+)+(1)/(2)O_(2)(g)+2e^(-) to H_(2)O(l),
Two half cell reactions are given as :
(i) `Fe_(aq)^(2+)+2e^(-) to Fe_((s)),E^(@)=-0.44" V "`
(ii) `2H_((aq))^(+)+(1)/(2)O_(2)(g)+2e^(-) to H_(2)O(l),E^(@)=+1.23" V "`
The `E^(@)` for the reaction
`Fe_(s)+2H^(+)+(1)/(2)O_(2)(g) to Fe_(aq)^(2+)+H_(2)O_(l)` is
A. `+1.67" V "`
B. `-1.67" V "`
C. `+0.79" V "`
D. `-0.79" V "`
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Correct Answer - A
(a) Subtract equation (i) from equation (ii) to get equation (iii) `E^(@)=(+1.23)-(-0.44)=+1.67" V "`.
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