Calculate e.m.f. of the cell containing nickel and copper electrodes. Given that : `E_(Ni^(2+)//Ni)^(@)=-0.25 V , E_(Cu^(2+)//Cu)^(@)=+0.34 V.`
Calculate e.m.f. of the cell containing nickel and copper electrodes. Given that :
`E_(Ni^(2+)//Ni)^(@)=-0.25 V , E_(Cu^(2+)//Cu)^(@)=+0.34 V.`
5 views
1 Answers
`E_(cell)^(@)=E_(cathode)^(@)-E_(anode)^(@)`
`=(E_(Cu^(2+)//Cu)^(@))-(E_(Ni^(2+)//Ni)^(@))=0.34-(-0.25)=0.59 V.`
5 views
Answered