Ethyl bromide on treatment with alcoholic KOH gives
Ethyl bromide on treatment with alcoholic KOH gives
A. Ethylene
B. Ethanol
C. Acetic acid
D. Ethane
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Correct Answer - A
`underset("bromide")underset("Ethyl")(C_(2)H_(5)Br)+underset("Alcoholic")(KOH)rarr underset("Ethylene")(C_(2)H_(4))+KBr+H_(2)O`
This reaction ios known as dehydrohalogenation.
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