When ethyl iodide and n-propyl iodide are allowed to react with sodium metal in ether, the number of alkanes that could be produced is
When ethyl iodide and n-propyl iodide are allowed to react with sodium metal in ether, the number of alkanes that could be produced is
A. only one
B. two alkanes
C. three alkanes
D. four alkanes
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Correct Answer - C
`C_(2)H_(5)I+ICH_(2)CH_(2)CH_(3)overset(2Na)rarr C_(2)H_(5)CH_(2)CH_(2)CH_(3)` (Pentane)
`2C_(2)H_(5)I+2Na rarr C_(2)H_(5)C_(2)H_(5)` (Butane)
`2CH_(3)CH_(2)CH_(2)I rarr underset(("Hexane"))(CH_(3)CH_(2)CH_(2)CH_(2)CH_(2)CH_(3))`
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