If a two digit number is choosen at random, what is the probability that the number chossen is a multiple of 3? A) 2/99 B) 1/3

Correct option is: B) \(\frac{1}{3}\)

Total No of two-digit numbers = 99 - 10 + 1 = 90.

(\(\therefore\) Smallest two digit number is 10 & highest two - digit number is 99)

The smallest two-digit number that is a multiple of 3 is 12 

= 3 \(\times4\) and the highest two-digit number that is multiple of 3 is 99 = 3 \(\times\) 33.

\(\therefore\) Total No. of two -digit numbers which are multiples of 3 = 33 -4 + 1 = 30

\(\therefore\) The probability that the number chosen is a multiple of 3

= \(\frac {Total \,No. \,of \,two-digit \,numbers \,that \,are \,multiple \,of \,3}{Total \,No. \,of \,two-digit \,numbers}\)= \(\frac {30}{90} = \frac 13\)

Correct option is: B) \(\frac{1}{3}\)