If K1 ≤ P ≤ K2 where P is probability of any event of random experiment, then the possible maximum K2 + possible least value of K1 is …………
If K1 ≤ P ≤ K2 where P is probability of any event of random experiment, then the possible maximum K2 + possible least value of K1 is …………
A) 1
B) 0
C) 2
D) cannot be determined
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Correct option is: A) 1
\(\because\) P is probability of any event of random experiment.
\(\therefore\) 0 \(\leq\) P \(\leq\) 1
But given that \(K_1\) \(\leq\) P \(\leq\) \(K_2\)
\(\therefore\) 0 \(\leq\) \(K_1\) \(\leq\) P \(\leq\) \(K_2\) \(\leq\) 1
\(\therefore\) Possible maximum value of \(K_2\) is 1
and possible least value of \(K_1\) is 0.
\(\therefore\) Possible maximum \(K_2\) + possible least value of \(K_1\)
= 1 + 0 = 1
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