Three unbiased coins are tosseed. The probability of getting at most two heads is ………… A) 3/8 B) 1/2 C) 3/4
Three unbiased coins are tosseed. The probability of getting at most two heads is …………
A) 3/8
B) 1/2
C) 3/4
D) 7/8
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Correct option is: D) \(\frac{7}{8}\)
\(\therefore\) Possible outcomes are (HHH, HHT, HTH, THH, HTT, THT, TTH, TTT)
\(\therefore\) n (s) = Total No of outcomes = 8.
Let E be the event of getting at most two heads
E = (HHT, HTH, THH, HTT, THT, TTH, TTT)
\(\therefore\) n (E) = 7
\(\therefore\) P (E) = \(\frac {n(E)}{n(S)} = \frac 78\)
Hence, the probability of getting at most two heads is \(\frac{7}{8}\)
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