If g(x) = x^6 + 3x^4 – 24x^2 + 3 find g(1), g(2) and g(3). A) g(1) = -12, g(2) = 19, g(3) = 759
If g(x) = x6 + 3x4 – 24x2 + 3 find g(1), g(2) and g(3).
A) g(1) = -17, g(2) = 19, g(3) = 759
B) g(1) = 12, g(2) = 19, g(3) = 758
C) g(1) = -12, g(2) = -19, g(3) = -759
D) g(1) = -12, g(2) = -19, g(3) = 759
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Correct option is (A) g(1) = -17, g(2) = 19, g(3) = 759
\(\because g(x)=x^6+3x^4-24x^2+3\)
\(\therefore\) g(1) = 1+3-24+3 = -17,
\(g(2)=2^6+3.2^4-24.2^2+3\)
= 64 + 48 - 96 + 3
= 115 - 96 = 19 and
\(g(3)=3^6+3.3^4-24.3^2+3\)
= 729 + 243 - 216 + 3
= 975 - 216
= 759
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