Which `0.01` mole of a cobalt complex is treated with excess silver nitralte solution`4.305` g silver chloride is precipitated. The formula of the com

Question

Which `0.01` mole of a cobalt complex is treated with excess silver nitralte solution`4.305` g silver chloride is precipitated. The formula of the com

Which `0.01` mole of a cobalt complex is treated with excess silver nitralte solution`4.305` g silver chloride is precipitated. The formula of the complex is
A. `[Co(NH_(3))_(3)Cl_(3)]`
B. `[Co(NH_(3))_(5)Cl]Cl_(2)`
C. `[Co(NH_(3))_(6)]Cl_(3)`
D. `[Co(NH_(3))_(4)Cl_(2)]No_(3)`

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - C
`4.305` g AgCl = `4.305/143.5` mole = `0.03` mole
As `0.01` mole of the complex gives `0.03` mole of AgCl, this shows that there are 3 ionisable Cl.
`:.` the formula is `[Co(Nh_(3))_(6)]Cl_(3)` .

5 views Answered 2023-02-05 15:29