`[Cu(NH_(3))_(4)]^(2+)` is a square planar complex.The number of unpaired electrons and hybrid state of copper are respectively
`[Cu(NH_(3))_(4)]^(2+)` is a square planar complex.The number of unpaired electrons and hybrid state of copper are respectively
A. 4, `dsp^(2)`
B. 1, `sp^(2)`
C. 1, `dsp^(2)`
D. 4s, `sp^(3)`
4 views
1 Answers
Correct Answer - C
`[Cu(NH_(3))_(4)]^(2+)` is square planar with one unpaired electron and `dsp^(2)`-hybridization of Cu.
4 views
Answered