0.3 g of an acid is neutralized by `40 cm^(3)` of 0.125 N NaOH. Equivalent mass of the acid is
0.3 g of an acid is neutralized by `40 cm^(3)` of 0.125 N NaOH. Equivalent mass of the acid is
A. `60`
B. `45`
C. `30`
D. `63`
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Correct Answer - A
`40cm^(3)` of 0.125 N NaOH neutralize acid = 0.3 g
`1000 cm^(3)` of 1 N NaOH will neutralize acid
`= (0.3)/(40)xx(1000)/(0.125)g = 60 g`
`1000cm^(3)` of 1 N NaOH contains one gram equivalent of the acid. Hence equivalent weight of acid=60
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