The decomposition of a certain mass of `CaCO_(3)` gave `11.2 dm^(3)` of a `CO_(2)` at S.T.P. The mass of KOH required to completely neutralize the gas
The decomposition of a certain mass of `CaCO_(3)` gave `11.2 dm^(3)` of a `CO_(2)` at S.T.P. The mass of KOH required to completely neutralize the gas is
A. `56 g`
B. `28g`
C. `42g`
D. `20g`
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Correct Answer - A
`underset(112g)underset(2(39+16+1))(2KOH)+underset("at S.T.P.")underset(22.4 L)(CO_(2))toK_(2)CO_(3)+H_(2)O`
`22.4 dm^(3)` of `CO_(2)` at N.T.P. required KOH = 112 g
`11.2 dm^(3)` of `CO_(2)` at S.T.P. will require KOH = 56 g
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