The correct increasing order of bond dissociation energy for `N_2, O_2, F_2, Cl_2` is
The correct increasing order of bond dissociation energy for `N_2, O_2, F_2, Cl_2` is
A. `N_2 lt O_2 lt F_2 lt Cl_2`
B. `F_2 lt Cl_2 lt O_2 lt N_2`
C. `F_2 lt Cl_2 lt N_2 lt O_2`
D. `N_2 lt Cl_2 lt F_2 lt O_2`
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Correct Answer - B
Bond dissociation energy of `F_2` is less than `Cl_2`
`F_2 lt Cl_2`
Bond dissociation energies of `O_2` (O=O) and `N_2(N = N)` are more than `Cl_2` or `F_2` which contains only single bonds. Out of `N_2` (with a triple bond) and `O_2` (with a double bond), bond dissociation energy of `N_2` is more than `O_2`. Therefore correct order is : `F_2 lt Cl_2 lt O_2 lt N_2`
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