What is the entropy that takes place in conversion of 1 mol of `alpha-`tin to 1 mol `beta -` tin at `17^(@)C`, 1 atm pressure if enthalpy of transition is 2.90 kJ `mol^(-1)` ?
A. `1.0 kJ mol^(-1)`
B. `7.32 JK^(-1) mol^(-1)`
C. `10JK^(-1)mol^(-1)`
D. `100JK mol^(-1)`

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Correct Answer - C
`DeltaS=(DeltaH_("transition"))/(T_("transition"))=5 xx 10^(-11)mol^(-1)`
`=(2.90 xx 1000J mol^(-1))/(290)=10JK^(-1)mol^(-1)`

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