20mL of 0.5 M HCl and 35 mL of 0.1 N NaOH are mixed. The resulting solution will

Question

20mL of 0.5 M HCl and 35 mL of 0.1 N NaOH are mixed. The resulting solution will

20mL of 0.5 M HCl and 35 mL of 0.1 N NaOH are mixed. The resulting solution will
A. be neutral
B. be basic
C. turn phenolphthalein
D. turn methyl orange solution red

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

Related Questions

To a 4L of 0.2M solution of `NaOH, 2L` of `0.5M NaOH` are added. The molarity of resulting solution is

2 Answers 6 Views

2.5 litre of `1M NaOH` solution is mixed with another 3 litre solution of `0.5M NaOH` solution. Then the molarity of the resulting solution is

2 Answers 9 Views

0.365g of HCl gas was passed through 100 `cm^(3)` of 0.2 M NaOH solution. The pH of the resulting solution would be

2 Answers 4 Views

50 mL of 0.1 M HCl and 50 mL of 2.0 M NaOH are mixed. The pH of the resulting solution is

2 Answers 4 Views

`50 cm^(3)` of 0.2 N HCl is titrated against 0.1 N NaOH solution. The titration is discontinued after adding `50 cm^(3)` of NaOH solution. The remaini

2 Answers 5 Views

20 mL of `C_(2)H_(5)OH` when mixed with 20ml of water,the volume of the resulting solution is

2 Answers 4 Views

What volume of aqueous solution of NaOH that is `80%` by mass NaOH, contanis 0.4 mol of NaOH. Density of solution is `0.8 gm//ml`.

2 Answers 7 Views

2.5 litre of 1M NaOH solution is mixed with a 3.0 litres of 0.5 M NaOH solution. The molarity of the resulting solution is :

2 Answers 5 Views

300 gm, `30%`(w/w) NaOH solution is mixed with 500 gm `40%`(w/w) NaOH solution. What is `%` (w/v) NaOH if density of final solution is 2 gm/mL?

2 Answers 5 Views

Assertion(A) : Heat of neutralisation of `HCl` and `NaOH` is same as that of `H_(2)SO_(4)` with `NaOH`. Reason(R ) : `HCl`, `H_(2)SO_(4)` and `NaOH` a

2 Answers 7 Views

Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - D
0.5 HCl `=0.5 M HCl`
0.1 N NaOH `=0.1 ` MNaOH ltBRgt `HCl +NaOH rarr M xx V = 0.5 xx 20 xx 10^(-3)`
`=10^(-2)`
Moles of NaOH `=M xx V =0.1 xx 35 xx 10^(-3)`
`=3.5 xx 10^(-3)`
As the solutions on mixing will contains excess of HCl `(10^(-2) gt 3.5 xx 10^(-3))`, it will turn methyl orange red.

4 views Answered 2023-02-05 15:29