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The solubility product of barium sulphate is `1.5 xx 10^(-9)` at `18^(@)C` . Its solubility in water at `18^(@)C` is
A. `1.5 xx 10^(-9)` mol `L^(-1)`
B. `1.5 xx 10^(-5) mol L^(-1)`
C. `3.9 xx 10^(-9) mol L^(-1)`
D. `3.9 xx 10^(-5) mol L^(-1)`

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Correct Answer - D
`BaSO_(4) rarr Ba^(+2)+SO_(4)^(2-)`
`:. ` Solubility `=(K_(sp))^(1//2)`
`=(1.5 xx 10^(-9))^(1//2)=3.87 xx 10^(-5)mol L^(-1)`

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