If log(x + y) = log( 3x - 3y/2) then log x – log y = …………
If log(x + y) = log(\(\cfrac{3x-3y}2\) ) then log x – log y = …………
(A) log 6
(B) log 3
(C) log 5
(D) log 2
5 views
2 Answers
Correct option is (C) log 5
Given that \(log\,(x+y)=log\,(\frac{3x-3y}{2})\)
\(\therefore\) \(x+y=\frac{3x-3y}{2}\)
\(\Rightarrow\) 2x+2y = 3x - 3y
\(\Rightarrow\) 3x - 2x = 2y+3y
\(\Rightarrow\) x = 5y
\(\Rightarrow\) \(\frac xy=5\)
\(\therefore\) log x – log y \(=log\,\frac xy\)
= log 5
5 views
Answered