The entropy change for the fusion of `1 mol` of a solid which melts at `27^(@)C` is (latent heat of fusion `=600 kcal mol^(-1)`)

Question

The entropy change for the fusion of `1 mol` of a solid which melts at `27^(@)C` is (latent heat of fusion `=600 kcal mol^(-1)`)

The entropy change for the fusion of `1 mol` of a solid which melts at `27^(@)C` is (latent heat of fusion `=600 kcal mol^(-1)`)
A. `2 cal deg^(-1)`
B. `22.2 cal deg^(-1)`
C. `180 kcal deg`
D. `0.5 cal^(-1)deg`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - A
`DeltaS_(fus)=(DeltaH_(fus))/(T)=(600)/(300)=2 cal deg^(-1)`

4 views Answered 2023-02-05 15:29