The equivalent conductances at infinite dilution of HCl and NaCl are 426.15 and 126.15 mho `cm^(2) g eq^(-1)` respectively. It can be said that the mo

Question

The equivalent conductances at infinite dilution of HCl and NaCl are 426.15 and 126.15 mho `cm^(2) g eq^(-1)` respectively. It can be said that the mo

The equivalent conductances at infinite dilution of HCl and NaCl are 426.15 and 126.15 mho `cm^(2) g eq^(-1)` respectively. It can be said that the mobility of :
A. `H^(+)` ions is much more than that of `Cl^(-)` ions
B. `Cl^(-)` ions is much more than that of `H^(+)` ions
C. `H^(+)` ions is much more than that of `Na^(+)` ions
D. `Na^(+)` ions is much more than that of `H^(+)` ions

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - C
`^^_((aq))^(@)HClgtgtA^_(eq)^(@)(NaCl)`. Since `Cl^(-)` ions are common. This means their ionic conductance of `H^(+)gtgt` ionic conductance `prop` ionic mobility.
`lambda_("cation")propmu_("cation"),lambda_("anion")propmu_("anion")`
`therefore` H ions have much greater mobility than `Na^(+)` ion.

5 views Answered 2023-02-05 15:29