100 ml `Fe(OH)_(3)` is coagulated by 10 ml 1N `Na_(2)SO_(4)`. Then what will be coagulation value of `Na_(2)SO_(4)`?
100 ml `Fe(OH)_(3)` is coagulated by 10 ml 1N `Na_(2)SO_(4)`. Then what will be coagulation value of `Na_(2)SO_(4)`?
A. 5
B. 10
C. 50
D. 100
4 views
1 Answers
Correct Answer - C
100 ml `Fe(OH)_3 ` is coagulated by =`10xx1/2`=5 milli mol
1 mol `Fe(OH)_3` is coagulated by = `5/100`
1000 ml `Fe(OH)_3` is coagulated by `=(1000xx5)/100`=50
4 views
Answered