For the concentration cell `Cu|Cu^(2+)(C_(1))||Cu^(2+)(C_(2))|Cu,DeltaG` will be negative if `Pt(Cl_(2)-P_(1))|HCl(0.1M)| Pt(Cl_(2)-P_(2))` the cell r

Question

For the concentration cell `Cu|Cu^(2+)(C_(1))||Cu^(2+)(C_(2))|Cu,DeltaG` will be negative if `Pt(Cl_(2)-P_(1))|HCl(0.1M)| Pt(Cl_(2)-P_(2))` the cell r

For the concentration cell
`Cu|Cu^(2+)(C_(1))||Cu^(2+)(C_(2))|Cu,DeltaG` will be negative if
`Pt(Cl_(2)-P_(1))|HCl(0.1M)| Pt(Cl_(2)-P_(2))` the cell reaction is spontaneous if
A. `p_(1)=p_(2)`
B. `p_(1)gtp_(2)`
C. `p_(2)gtp_(1)`
D. None of these.

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Correct Answer - C
It is a concentration cell reversible w.r.t. anion
`2Cl^(-)(0.1M)rarrCl_(p_(1))+2e^(-)`
`Cl_(2)(p_(2))+2e^(-)rarr2Cl^(-)(0.1M)`
`Cl_(2)(p_(2))+2e^(-)rarr2Cl^(-)(0.1M)`
`Cl_(2)(p_(2))rarrCl_(2)(p_(1))`
`E_("Cell")=-(0.0591)/(5)"log"(p_(1))/(p_(2))`
`=(0.0591)/(5)"log"(p_(1))/(p_(1))`
`E_("cell")gt0` if `p_(2)gtp_(1)`