The oxidation number, of C in `CH_(4). CH_(3)CI, CH_(2)CI_(2), CHCl_(3) and C Cl_(4)` are respectively:
A. `-4,-2,0,+2,+4`
B. `+2,4,0,-2,-4`
C. `4,2,0,-2,-4`
D. `0,2,-2,4,4`

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Correct Answer - A
`CH_(4),x+4(-1)=0or x=+4`
`CH_(3)Cl,x+3(+1)+(-1)=0orx=-2`
`CH_(2)Cl_(2)` given in Q-6
`CHCl_(3),x+1+3(-1)=0orx=+2`
`C Cl_(4),x+3(-1)=0or x=+4`.

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