The addition of HI in the presence of peroxide does not show anti-Markovnikov behavior because
The addition of HI in the presence of peroxide does not show anti-Markovnikov behavior because
A. the HI band is too strong not to be broken homolytically
B. HI is reducing agent
C. I free radical so formed readily combine with each other to give `I_(2)` molecule
D. I comine with H to give back HI
4 views
1 Answers
Correct Answer - C
H-I bond is weak (71/Kcal/mole) breaks homolytcically 1 free radical, it so formed combine each other produces `I_(2)` molecule.
4 views
Answered