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Decreasing order of oxidising property of tetrapositive lanthanide is
A. `Dy ^(4+)gt De^(4+) gt Pr ^(4+) gt Nd^(4+)`
B. `Dy ^(4+)Nd^(4+)gtPr^(4+) gt Ve^(4+)`
C. `Ce ^(4+) gt Pr ^(4+) gt Nd^(4+) gt Dy^(4+)`
D. `Nd ^(4+) gt Pr ^(4+) gt Dy^(4+)gt Ce ^(4+)`

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1 Answers

Correct Answer - B
We know that, all tetra positive lanthanides are oxidising agent, having tendenct to gain electrons. Tendency to gain electron depends upon ionic size. Smaller that ionic size, more the tendency to gain electron and stronger will be oxidising agent. From Ce to Dy size of the tetrapositive cation decreases.
`Dy^(4+).` Hence `Dy ^(4+)` has more tendency to gain electron and acts as strongest oxidising agent. Oxidising property of ion decreases as
`Dy^(4+)gt Nd ^(4+) gt Pr^(4+) gt Tb ^(4+) gt Ce^(4+).`

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