A and B are two metals with threshold frequencies `1.8xx10^(14)Hz and 2.2xx10^(14)Hz`. Two identical photons of energy of 0.825 eV each are incident o

Question

A and B are two metals with threshold frequencies `1.8xx10^(14)Hz and 2.2xx10^(14)Hz`. Two identical photons of energy of 0.825 eV each are incident o

A and B are two metals with threshold frequencies `1.8xx10^(14)Hz and 2.2xx10^(14)Hz`. Two identical photons of energy of 0.825 eV each are incident on them. Then photoelectrons are emitted in take `h=6.6xx10^(-34)J//s`
A. B alone
B. A alone
C. neither A nor B
D. Both A and B

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - B
(b) : `phi_(0A)=(hv_(0))/(e)eV=((6.6xx10^(-34))xx(1.8xx10^(14)))/(1.6xx10^(-19))eV`
=0.74eV
`phi_(0B)=((6.6xx10^(-34))xx(2.2xx10^(14)))/(1.6xx10^(-19))eV=0.91eV`
Since the incident energy 0.825 eV is greater than 0.74 eV and less than 0.91 eV, so photoelectrone are emitted from metal A only.

5 views Answered 2023-02-05 15:29