In the question number 44, the phase difference between the voltage across the source and current is
A. `80.2^(@)`
B. `31^(@)`
C. `50.2^(@)`
D. `38.2^(@)`

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1 Answers

Correct Answer - B
Here, `X_(L)-X_(C )=3.6Omega, R=6 Omega`
Phase difference `phi = tan^(-1)((X_(L)-X_(C ))/(R ))`
`therefore phi = tan^(-1)((3.6)/(6))=tan^(-1)(0.6)=31^(@)`

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