i) `AgCl_((S)) + e^(-) to Ag_((S)) + Cl_((aq))^(-) E^(@) = 0.22` V . ii) `Ag_((aq)) e^(-) to Ag_((S)) , E^(@) = - 0.8 V` then SRP for the reaction is

Question

i) `AgCl_((S)) + e^(-) to Ag_((S)) + Cl_((aq))^(-) E^(@) = 0.22` V . ii) `Ag_((aq)) e^(-) to Ag_((S)) , E^(@) = - 0.8 V` then SRP for the reaction is

i) `AgCl_((S)) + e^(-) to Ag_((S)) + Cl_((aq))^(-) E^(@) = 0.22` V .
ii) `Ag_((aq)) e^(-) to Ag_((S)) , E^(@) = - 0.8 V`
then SRP for the reaction is
`AgCl_((S)) to Ag_((aq))^(+) + Cl_((aq))^(-) ` is
A. 1.20 V
B. `-1.20` V
C. `0.58` V
D. `+ 0.58` V

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - C
`AgCl_((S)) + e^(-) to Ag_((S)) + Cl_((aq))^(-) E^(@) = 0.22` V
`Ag_((aq))^(+) + e^(-) to Ag_((S)) E^(@) = -0.8 ` V
`therefore` Hence for the overall reaction
`AgCl_((S)) to Ag_((aq))^(+) + Cl_((aq))^(-) ` is = `0.22 - 0.80 = -0.58` V

5 views Answered 2023-02-05 15:29