In the electrochemical reaction, `2Fe^(3+)+Zn rarr Zn^(2+) + 2Fe^(2+)` increasing the concentration of `Fe^(2+)`:
In the electrochemical reaction, `2Fe^(3+)+Zn rarr Zn^(2+) + 2Fe^(2+)` increasing the concentration of `Fe^(2+)`:
A. increasing cell emf
B. increasing the current flow
C. decreases the cell emf
D. alters the pH of the solution .
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Correct Answer - C
`E_("cell") = E_("cell")^(@) - (RT)/(nF) "ln" ([Fe^(2+)]^(2))/([Fe^(3+)]^(2))` .
Increasing `[Fe^(2+)]` decreases `E_("cell")` .
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