For the cell `Zn |Zn^(2+) | | Cu^(2+) | Cu` , if the concentration of `Zn^(2+)` and `Cu^(2+)` ions is doubled , the emf of the cell
A. doubles
B. reduces to half
C. remains same
D. becomes zero

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Correct Answer - C
`E_("cell") = E_("cell")^(@) + (0.059)/(2) "log" ([Cu^(2+)])/([Zn^(2+)])` , Thus on doubling concentration of both `Cu^(2+) and Zn^(2+)` , there will be no effect on `E_("cell")`.

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