The wt. percent of `NO_(3)^(-)` in the solute in a solution is 20. The volume of solvent containing 60 g of solute (d = 1.2 g/cc)

Question

The wt. percent of `NO_(3)^(-)` in the solute in a solution is 20. The volume of solvent containing 60 g of solute (d = 1.2 g/cc)

The wt. percent of `NO_(3)^(-)` in the solute in a solution is 20. The volume of solvent containing 60 g of solute (d = 1.2 g/cc)
A. `0.24 dm^(3)`
B. `0.12 dm^(3)`
C. `1.2 dm^(3)`
D. `0.2 dm^(3)`

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - D
Wt. of solvent = Wt. of solution- Wt. of solute
`=100 - 20 =80g`
20 g of solute is present in 80 g of solvent.
60 g of solute will be present in `(80 xx 60)/20=240 g
`:."Volume of solvent" = (Wt)/"density"=240/1.2=200 cm ^(3)`
= `0.2 dm^(3)`

5 views Answered 2023-02-05 15:29