when concentration of reactant is incresed eighteen times the rate becomes two times , the rate of reaction is

Question

when concentration of reactant is incresed eighteen times the rate becomes two times , the rate of reaction is

when concentration of reactant is incresed eighteen times the rate becomes two times , the rate of reaction is
A. `1`
B. `(1)/(2)`
C. `(1)/(3) `
D. `(1)/(4)`

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - C
`(k_(2))/(k_(1))[(A_(2))/(A_(1))]^(n) or 2=(8)^(n) therefore = (1)/(3)`

5 views Answered 2023-02-05 15:29