The ratio of the times of 99.9 % of the reaction to complete and half of the reaction to complete is
The ratio of the times of 99.9 % of the reaction to complete and half of the reaction to complete is
A. 2
B. 4
C. 8
D. 10
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Correct Answer - D
`t_(1//2)=(2.303)/(k) log ""(100)/(0.1)=(2.303)/(k)x3`
`t_(1//2)=(2.303)/(k)log2""=(2.303)/(k)xx0.301`
`(t)/(t_(1//2))=(3)/(0.301)~~10`
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