A coil having 50 turns and an area of `800 cm^(2)` is held with its plane perpendicular to uniform magnetic field of induction `5xx10^(-5)Wb//m^(2)`.

Question

A coil having 50 turns and an area of `800 cm^(2)` is held with its plane perpendicular to uniform magnetic field of induction `5xx10^(-5)Wb//m^(2)`.

A coil having 50 turns and an area of `800 cm^(2)` is held with its plane perpendicular to uniform magnetic field of induction `5xx10^(-5)Wb//m^(2)`. If it is pulled out of the field in 2 second, then the emf induced in the coil will be
A. `10^(-4)V`
B. `10^(-5)V`
C. `10^(-6)V`
D. `10^(-8)V`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - A
`e=(dphi)/(dt)=(phi_(1)-phi_(2))/(dt)`
`=(nAB_(1)costheta-nAB_(2)costheta)/(dt)`
`=(50xx800xx10^(-4)xx5xx10^(-5)xxcos0-0)/(2)`
`=10^(-4)V`

4 views Answered 2023-02-05 15:29