A beam of light is incident at polarising angle `theta ` on air-glass interface. If ` lambda_a and lambda_g` are the wavelength of light in air and gl

Question

A beam of light is incident at polarising angle `theta ` on air-glass interface. If ` lambda_a and lambda_g` are the wavelength of light in air and gl

A beam of light is incident at polarising angle `theta ` on air-glass interface. If ` lambda_a and lambda_g` are the wavelength of light in air and glass respectively then
A. `lambda_a=lambda_g cot theta `
B. `lambda_g= lambda_a cot theta `
C. `lambda_a=lambda_g tan^(2) theta `
D. `lambda_g = lambda_a tan^(2) theta `

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - B
`n= tan theta and n=(V_a)/(V_g)=(lambda_a)/(lambda_g)`
`:. (lambda_a)/(lambda_g)=tan theta :. "" lambda_g=(lambda_a)/(tan theta)=lambda_a cot theta `

4 views Answered 2023-02-05 15:29