The current, in a potentiometer wire of 100 cm length, is adjusted to give a null point at 5 cm with standard cell of e.m.f. 1.018 V. The e.m.f. of ce
The current, in a potentiometer wire of 100 cm length, is adjusted to give a null point at 5 cm with standard cell of e.m.f. 1.018 V. The e.m.f. of cell which gives null point of 60 cm is
A. 1.221V
B. 2.22V
C. 3.22V
D. 4.22V
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Correct Answer - A
`(E_(1))/(E_(2))=(l_(1))/(l_(2))`
`:.E_(2)=(l_(2))/(l_(1))E_(1)=(60xx10^(-2)xx1.018)/(50xx10^(-2))=1.221V`
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