A closed conducting sphere is positively charged such that the surface charge density is `17.7xx10^(-12)C//m^(2)`. If the dielectric constant of the m
A closed conducting sphere is positively charged such that the surface charge density is `17.7xx10^(-12)C//m^(2)`. If the dielectric constant of the medium surrounding the conductor is 100, then electric field intensity at a point just outside it will be
A. `1.02 V//m`
B. `0.02 V//m`
C. `1.22 V//m`
D. `2.22 V//m`
4 views
1 Answers
Correct Answer - B
`E=sigma/(epsi_(0)k)=(17.7xx10^(-12))/(8.85xx10^(-12)xx100)=0.02V//m.`
4 views
Answered