If path difference between is `(11 lambda)/(4)` then the phase difference between two waves will be

Question

If path difference between is `(11 lambda)/(4)` then the phase difference between two waves will be

If path difference between is `(11 lambda)/(4)` then the phase difference between two waves will be
A. `11 pi //2`
B. ` 5 pi//2`
C. `13pi//2`
D. `7pi//2`

Monjur Alahi

6 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - A
Phase diff. `=(2pi)/(lambda)` path diff. `=(2pi)/(lambda)xx(11lambda)/(4)`
`=(2pi xx11)/( 4) =(11 pi)/(4)`

6 views Answered 2023-02-05 15:29