Two coherent sources have intensity ratio of 100 : 1, and are used for obtaining the phenomenon of interference. Then the ratio of maximum and minimum
Two coherent sources have intensity ratio of 100 : 1, and are used for obtaining the phenomenon of interference. Then the ratio of maximum and minimum intensity will be –
A. `121:81`
B. `100:1`
C. `101:99`
D. `100:99`
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Correct Answer - A
`(I_(1))/(I_(2))=(100)/(1),(I_("max"))/(I_("min"))= ?`
`(I_(1))/(I_(2))=(a_(1)^(2))/(a_(2)^(2))=(100)/(1) :. (a_(1))/(a_(2))=(10)/(1)`
`:.a_(1)=10a_(2)`
`(I_("max"))/(I_("min"))=((a_(1)+a_(1))^(2))/((a_(1)-a_(2))^(2))`
`((10a_(1)+a_(1))^(2))/((10a_(1)-a_(2))^(2))`
`(121a_(2)^(2))/(81_(2)^(2))`
`=(121)/(81)`
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