In a biprism experiment, the wavelenght of monochromatic light is `6000Å`. The distance between two virtual images is 6 mm . The number of fringes for

Question

In a biprism experiment, the wavelenght of monochromatic light is `6000Å`. The distance between two virtual images is 6 mm . The number of fringes for

In a biprism experiment, the wavelenght of monochromatic light is `6000Å`. The distance between two virtual images is 6 mm . The number of fringes formed per mm on a screen placed at a distance of 1 m is
A. 5
B. 10
C. 15
D. 20

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - B
`beta=(D)/(d) lambda =(1xx6xx10^(-7))/(6xx10^(-3))=0.1 mm`
Thus,
No. of fringes formedper mm of screen `=(1)/(0.1)=10`

5 views Answered 2023-02-05 15:29